Add (th, st, nd, rd, th) to the end of a number

Snippet Code

This simple and easy function will take a number and add "th, st, nd, rd, th" after it. Example 10 to 10th.


<?php

function ordinal($cdnl){

    $test_c = abs($cdnl) % 10;

    $ext = ((abs($cdnl) %100 < 21 && abs($cdnl) %100 > 4) ? 'th'

            : (($test_c < 4) ? ($test_c < 3) ? ($test_c < 2) ? ($test_c < 1)

            ? 'th' : 'st' : 'nd' : 'rd' : 'th'));

    return $cdnl.$ext;

} 

for($i=1;$i<100;$i++){

    echo ordinal($i).'<br>';

}

?>

Snippet Comments

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Dan
2010-04-23 00:00:00

Here is mine, it doesn't give 11st, 12nd and 13rd like most do. [code] function make_ranked( $rank ) { $last = substr( $rank, -1 ); $seclast = substr( $rank, -2, -1 ); if( $last > 3 || $last == 0 ) $ext = 'th'; else if( $last == 3 ) $ext = 'rd'; else if( $last == 2 ) $ext = 'nd'; else $ext = 'st'; if( $last == 1 && $seclast == 1) $ext = 'th'; # Avoid 11st if( $last == 2 && $seclast == 1) $ext = 'th'; # Avoid 12nd if( $last == 3 && $seclast == 1) $ext = 'th'; # Avoid 13rd return $rank . $ext; }[/code] Not sure if these comments have code formating so may be a little messy, but works :)

mkei85
2009-11-30 00:00:00

Simple one: function ordinal($num) { $last=substr($num,-1); if($last>3 or $last==0) $ext='th'; else if($last==3) $ext='rd'; else if($last==2) $ext='nd'; else $ext='st'; return $num.$ext; }

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